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There is only one possible combination as a combination is the same no matter what the order is. There are 120 permutations, which is where the order does matter.
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∙ 6y ago
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A combination lock on a suitcase has 5 wheels each labeled with digits 1 to 8 How many 5 digit combination lock codes are possible if no digit can be repeated?
6,720 combinations.
For her bicycle Lisa has a chain and a combination lock that has a 4-digit combination where each digit can range from 0 - 9 If adjacent digits must be different how many possible combinations can?
10x9x9x9
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many different three digit palindromes can you make using only the digits 1and 2?
There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.
A combination lock on a suitcase has 5 wheels each labeled with digits 1 to 8 How many 5 digit combination lock codes are possible if no digit can be repeated?
6,720 combinations.
For her bicycle Lisa has a chain and a combination lock that has a 4-digit combination where each digit can range from 0 - 9 If adjacent digits must be different how many possible combinations can?
10x9x9x9
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
If a digital combination lock on a phone has 4 spaces with digits 0 to 9. How many 4 digit combination lock codes are possible?
104 or 10000
How many number combinations possible from a 13 digit number?
There is only one possible combination of a 13 digit number created from 13 digits. In a combination, the order of the digits does not matter so that 123 is the same as 132 or 312 etc. If there are 13 different digits (characters) there is 1 combination of 13 digits 13 combinations of 1 or of 12 digits 78 combinations of 2 or of 11 digits and so on There are 213 - 1 = 8191 in all. If the characters are not all different it is necessary to have more information.
If a digital combination lock on a phone has 4 spaces with digits 0 to 9 How many 4 digit combination lock codes are possible if any digit can be repeate?
I would have to say 10,000 possible combinations. (0000, 0001, 0002 through 9998, 9999)
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many four digit passwords are possible if repetition of digits is not allowed?
5040
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 4-digit numbers are possible if the hundreds digit is 8 and if repetition of digits is allowed?
-4
How many different three digit palindromes can you make using only the digits 1and 2?
There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.
How many 5 digit numbers are there with distinct digits?
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
