There is only one possible combination of a 13 digit number created from 13 digits.
In a combination, the order of the digits does not matter so that 123 is the same as 132 or 312 etc.
If there are 13 different digits (characters) there is
1 combination of 13 digits
13 combinations of 1 or of 12 digits
78 combinations of 2 or of 11 digits and so on
There are 213 - 1 = 8191 in all.
If the characters are not all different it is necessary to have more information.
If the same 7 digits are used for all the combinations then n! = 7! = 7*6*5*4*3*2*1 = 5040 combinations There are 9,999,999-1,000,000+1=9,000,000 7-digit numbers.
Too many to list here-see below.
if its not alphanumeric, 999999 variations
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
A 3-digit safe code can have combinations ranging from 000 to 999. This gives a total of 1,000 possible combinations, as each digit can be any number from 0 to 9. Therefore, the total number of combinations is 10 (choices for the first digit) × 10 (choices for the second digit) × 10 (choices for the third digit), which equals 1,000.
There are twelve possible solutions using the rule you stated.
There are 210 4 digit combinations and 5040 different 4 digit codes.
105 = 100000
There are 5,040 combinations.
There are 5,461,512 such combinations.
64
There are 27 possible combinations.
A 4-digit number can range from 0000 to 9999, which includes all combinations of four digits. Since each digit can be any number from 0 to 9 (10 options), the total number of combinations is calculated as (10^4). Therefore, there are 10,000 different combinations for a 4-digit number.
56 combinations. :)
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
Allowing leading zeros, 109 or 1 billion.