Short answer: 21
We can use combinatorics to solve this using the binomial coefficient to choose five elements out of a set of seven.
The equation for this is:
n!
------------
(n - k)! k!
Where n is the size of the set, k is the number of elements to choose, and "------------" is a crude attempt at a division sign.
In our case, n = 7, k = 5:
7!
------------
(7 - 5)! 5!
5040
------------
(2) (120)
5040
------------
240
5040 / 240 = 21
There are seven different possible magnetic quantum numbers or seven orbitals. In that cause the maximum number of electrons an f orbital will hold would be fourteen.
Yes seven is a prime number and the only numbers that will go in to seven is one and seven.
A binary number consists of two possible digits: 0 and 1. When using seven digits, each digit can independently be either 0 or 1. Therefore, the total number of binary numbers that can be formed with seven digits is (2^7), which equals 128. Thus, there are 128 different binary numbers that can be written using seven digits.
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
There is no such word as didgit.In theory there are 10,000,000 or ten million possible number but not all possible numbers are used. If 911 is for the emergency services then there will not be any numbers starting with 911. Otherwise the phone system will be unable to make out whether a pause after "911" is because the required number was actually or because the person is getting hold of the next 4 digits. There are other such special numbers.
42.
There is an infinite number of numbers that are not divisible by seven!
you whole numbers that seven go in to
To calculate the number of combinations possible with 8 numbers in a seven-number combination, you would use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 8 and r = 7. Plugging these values into the formula, you get 8C7 = 8! / (7!(8-7)!) = 8. Therefore, there are 8 possible combinations with 8 numbers in a seven-number combination.
When using the numbers one through seven, the total number of different combinations depends on how many numbers you want to select. If you're looking for all possible combinations of any length (from one to seven), you can calculate it using the formula for combinations, which is (2^n - 1) (where (n) is the total number of items) to account for all subsets except the empty set. Therefore, for seven numbers, there are (2^7 - 1 = 127) different combinations. If you specify a particular number of selections, the calculation would differ accordingly.
number of prime numbers which are in the seven times tables: 1 prime numbers are in the seven times tables: 7 only
The possible solutions are {5,5,9,n} where n is any number greater than or equal to 9.