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Roughly 195 million. Oh dear! At least that's the jackpot odds.

When you hear that you can win 50 or 100 million dollars if you play $1, your expected value (prize * expected probability of winning) is still less than $1.

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Q: How many possible number combinations in the poweball lottery?

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It isn't possible. Quite simply, if there were a way to do it, such a method would spread very quickly and that would ruin the lottery; there would be no more lottery.

55 x 54 x 53 x 52 x 51 x 50 = 20,872,566,000 possible combinations This includes counting combinations such as 1,2,3,4,5,6 and 1,2,3,4,6,5 and 6,5,4,3,2,1 and 4,2,3,1,5,6 as different. In a lottery, these are all considered to be the same. To get the number of combinations without regard to order, divide that number by 6!=6x5x4x3x2 which is 28,989,675

In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!

There are infinitely many numbers and so infinitely many possible combinations.

Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.

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It isn't possible. Quite simply, if there were a way to do it, such a method would spread very quickly and that would ruin the lottery; there would be no more lottery.

if i got everything right, its 1000

55 x 54 x 53 x 52 x 51 x 50 = 20,872,566,000 possible combinations This includes counting combinations such as 1,2,3,4,5,6 and 1,2,3,4,6,5 and 6,5,4,3,2,1 and 4,2,3,1,5,6 as different. In a lottery, these are all considered to be the same. To get the number of combinations without regard to order, divide that number by 6!=6x5x4x3x2 which is 28,989,675

2^n possible combinations

35

Since a number can have infinitely many digits, there are infinitely many possible combinations.

If repeats are allowed than an infinite number of combinations is possible.

At this point it is not possible to tell the two number VN lottery going out today.

There are infinitely many numbers and so infinitely many possible combinations.

In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!

Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.Calculate the number of possible combinations. The probability of winning is the reciprocal of that number.To calculate the number of combinations, suppose you have to choose r number out of n. Then the number of combinations is n!/[r!*(n-r)!] where n! = 1*2*3*...*n.Thus, for the UK national lottery (Lotto) n = 49, r = 6 so the relevant number is49*48*47*46*45*44/(6*5*4*3*2*1) = 13,983,816 or approx 14 million. Each combination is equally likely so the probability of winning is 1/14 million, approx.

128