if i got everything right, its 1000
Chat with our AI personalities
Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.
Four outcomes, three combinations.
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
I'm assuming they're three unique numbers. Thus, the first can be any of three, the second either of the remaining two, and the last is the last one left. Thus: combinations = 3 * 2 * 1 = 6 Or, more generally, the combinations of n numbers in such a problem is n factorial, denoted as "n!", which is every number from 1 to that number multiplied together.
Four of them.