If repeats are allowed than an infinite number of combinations is possible.
5435 441521 14241553 514152153 457745641 543646313 IDK TO HarD!
6 different combinations can be made with 3 items
1234567890
There are 9C3 = 84 combinations.
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The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.
5435 441521 14241553 514152153 457745641 543646313 IDK TO HarD!
To calculate the number of 3-digit combinations that can be made from the numbers 1-9, we can use the formula for permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the total number of options (10 in this case) and r is the number of digits in each combination (3 in this case). Therefore, the total number of 3-digit combinations that can be made from the numbers 1-9 is 10^3 = 1000.
1234567890
6 different combinations can be made with 3 items
1234567890
1234567890
1234567890
1234567890
1234567890 billon
Just 1.
1234567890