Prime factors of 1729: are 7, 13 and 19 which makes three of them
Check as many as you want, you won't find any divisors. 127 is prime.
23 is a prime number. It has two divisors.
95 = 5 * 19 both of which are prime, so 95 has 4 divisors as does any number that is the product of 2 primes. The divisors are 1,5,19 and 95.
149 is the only prime number betweeen 140 and 150.
The accepted definition of a prime number is a natural number which has exactly two distinct divisors. The number 1 has only one distinct divisor: itself. The number 0 can be said to have infinitely many distinct divisors.
To determine the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888, we can use the Prime Number Theorem. This theorem states that the density of prime numbers around a large number n is approximately 1/ln(n). Therefore, the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888 can be estimated by dividing ln(8888888888888888888888888888888888888888888888) by ln(2), which gives approximately 1.33 x 10^27 prime numbers.
Prime squares have three factors. There are 11 of them in that range.
1,2,3,4,6,8 are divisors of 48, so there are 6 divisors of 48 between 1 and 10
There are three prime numbers between 62 and 72: 61, 67, and 71. Prime numbers are those greater than 1 that have no divisors other than 1 and themselves. In this range, 63, 64, 65, 66, 68, 69, and 70 are not prime. Therefore, the primes are 67 and 71.
This can be an extension to the proof that there are infinitely many prime numbers. If there are infinitely many prime numbers, then there are also infinitely many PRODUCTS of prime numbers. Those numbers that are the product of 2 or more prime numbers are not prime numbers.
If you mean a regular six-sided die, there are 3: 2,3 and 5. Some people would argue that 1 is a prime number, but in fact 1 is not, as it only has one natural number divisor, while prime numbers have exactly two distinct natural number divisors.
If you multiply three different prime numbers ( p_1, p_2, ) and ( p_3 ), the product can be expressed as ( p_1^1 \times p_2^1 \times p_3^1 ). To find the number of positive divisors, you add 1 to each of the exponents and then multiply the results: ( (1+1)(1+1)(1+1) = 2 \times 2 \times 2 = 8 ). Therefore, the product will have 8 positive divisors.