It depends if the polygon is convex or concave but if it is a regular polygon it would have 560
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
It works out as having 5150 diagonals
120*(120-3)/2 = 7020
A tetra-decagon is a 14 sided polygon having 77 diagonals
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
A quadrilateral has 2 diagonals. It does not matter whether it is convex or not.
It has two diagonals
It is: 8-2 = 6 triangles
A convex hexadecagon has 8 diagonals.
That polygon is called a "triangle". It has no diagonals.
how many diagonals are there iin a polygon of 11 sides