Only one.
153 diagonals.
It is: 8-2 = 6 triangles
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.
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Only one.
In a polygon with n sides, we have n(n-3)/2 diagonals. In a convex polygon with n sides, you can draw n-3 diagonals from each vertex, but you are counting each one twice you so you need to divide by do. That is why we have n(n-3) divided by 2
64 sides = 64 angles From one angle you can draw (64 - 2) diagonals = 62. Lines from an angle to the immediately adjacent angles are sides, not diagonals.
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
153 diagonals.
It is: 8-2 = 6 triangles
infiniteImproved Answer:-The formula is: 0.5*(n2-3n) where n is the number of sides of the polygonSo: 0.5*(144-36) = 54 diagonals
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
A 5-sided polygon is called a pentagon. You can draw up to 5 diagonals in a pentagon.
You cannot draw a diagonal from a vertex to itself. So that is 1. Also, the diagonals to the adjacent vertices on either side will actually be the sides of the polygon, not diagonals. Those are the other 2.
20.
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