x^2 + 2x - 10
Does not factor
So apply the Quadratic Eq'n
x = [ -2 +/- sqrt[(2^2) - 4(1)(-10)]}/ 2(1)
x = { -2 +/- sqrt[4 + 40]} / 2
x = { -2 +/- sqrt(44]}/ 2
x = { - 2 +/- 6.6332...} / 2
x = -8.6332... / 2 = -4.3166....
&
x = 4.6332... / 2 = 2.3166...
Hencevthere are two answers.
It is a quadratic equation that has 2 solutions
No. It's a quadratic equation, and it has two solutions.
The discriminant is -439 and so there are no real solutions.
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
It is a quadratic equation that has 2 solutions
No. It's a quadratic equation, and it has two solutions.
The discriminant is -439 and so there are no real solutions.
The quadratic equation in standard form is: ax2 + bx + c = 0. The solution is x = [-b ± √b2- 4ac)] ÷ 2a You can use either plus or minus - a quadratic equation may have two solutions.
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions
Without an equality sign the given expression can't be considered to be an equation but if it equals 0 then using the quadratic equation formula will give its solutions.
Without an equality sign the given quadratic expression can't be classed as an equation but knowing how to use the quadratic equation formula would be helpful when given such problems.
1.1x2 + 3.3x + 4 = 6 First rearrange the equation to equal zero so that we can use the quadratic formula. 1.1x2 + 3.3x - 2 = 0 Using the quadratic formula, the solutions are x = -3.52 and x = 0.52 Both of these solutions are real, so the original equation has two real solutions.