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1.1x2 + 3.3x + 4 = 6

First rearrange the equation to equal zero so that we can use the quadratic formula.

1.1x2 + 3.3x - 2 = 0

Using the quadratic formula, the solutions are

x = -3.52 and x = 0.52

Both of these solutions are real, so the original equation has two real solutions.

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Q: How many real solution exist for the equation 1.1x2 plus 3.3x plus 4 equals 6?
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