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x2 + 5x - 15 = 0; a = 1, b = 5, and c = -15

x = [-b ± √(b2 - 4ac)]/(2a) the quadratic formula

x = [-5 ± √(52 - 4*1*-15)]/[2(1)] = [-5 ± √(25 + 60)]/2 = (-5 ± √85)/2

x = (-5 + √85)/2 or x = (-5 - √85)/2.

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10y ago
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Q: How many solutions dose squer x plus 5x -15 equals 0?
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