There are two terms which are 2x and 1
To simplify the expression ((1x^2 - 2x + 4) + (2x + 1) - (x^2 + 5)), first combine like terms. The (x^2) terms give (1x^2 - 1x^2 = 0). The (x) terms yield (-2x + 2x = 0), and the constant terms combine to (4 + 1 - 5 = 0). Thus, the simplified expression is (0).
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
By collecting like terms: 8z+4-2x
8x-4
7x+2 when simplified by collecting like terms
Slope-Intercept Form: y = -2x +1
starting with (x+3)+(2x-1)+(x-1)when this problem is written in a linear form it ends up being quite simple, you just have to combine like terms. Eliminating the parenthesis you getx+3+2x-1+x-1now group like terms togetherx+2x+x+3-1-1and solve to get 4x+1
4
Zero. The sum of anything and it's opposite is zero, that's how an opposite is defined. In this case, the opposite of 2x + 1 is -(2x + 1) = -2x - 1 by the distributive property. Adding like terms, 2x + -2x + 1 +-1 = 0 + 0 = 0.
Because all the terms have been divided by -1
(2x + 1)(2x + 1) or (2x + 1)2
To simplify the expression (2x + 23 - 2 - 1), first combine the constant terms: (23 - 2 - 1 = 20). Thus, the expression simplifies to (2x + 20).