0
What else can I help you with?
Factor 2x squared plus 2x plus xy plus y?
4
2x plus 2x plus 2x equals 6?
x=1
What is the average of 3x plus 1 and x-3?
Average = (sum of the items) / (number of items)Sum of the items = (3x + 1) + (x - 3) = 4x - 2Number of items = 2Average = (2x - 1)
What is 4x plus 1 equals 2x plus 12 equals?
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
Y equals 2x plus 1?
Y = 2x + 1
2x plus x plus opposite x plus -1 equals 7 plus 2 opposite x?
This is an unclear equation, actually some sort of addition. (Opposite means negative? Inverse?) 2x + x + (-x) + (-1) = 7 + 2 (-x) ?? 2x - 1 = 7 - 2x 4x = 8 x = 2
Find the sum 3x2 plus 2x plus 3 plus x2 plus x plus 1?
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
Ten plus the sum of two consecutive integers is 196?
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
What is 2x-1 plus 2x-1 plus 2x-1 plus 2x-1?
8x-4
What is the sum of 2x plus 1 and x times x minus 2x plus one?
(2x + 1) + (x*x - 2x + 1) = x^2 + 2x - 2x + 1 + 1 = x^2 + 2
Factor 2x squared plus 2x plus xy plus y?
4
Factor completely 4x2 plus 4x plus 1?
(2x + 1)(2x + 1) or (2x + 1)2
2x plus 2x plus 2x equals 6?
x=1
-2x plus 1 equals 2x plus 1?
x = 0
What is the second number of the sum of four consecutive odd integers 28458968?
Four consecutive odd integers: [2x-1], [2x+1], [2x+3], [2x+5].Their sum: (2x-1) + (2x+1) + (2x+3) + (2x+5) = 8x + 8 = 8(x+1) = 28,458,968(x+1) = 28,458,968/8 = 3,557,371x = 3,557,370The numbers are:7,114,739=> 7,114,741
What is the average of 3x plus 1 and x-3?
Average = (sum of the items) / (number of items)Sum of the items = (3x + 1) + (x - 3) = 4x - 2Number of items = 2Average = (2x - 1)
Create a pascal program which outputs sum of series 1 plus 2multiply3 plus 4multiply5multiply6 plus 7multiply8multiply9multiply10 plus?
f(x) = 1 + 2*3 + 4*5 + ... (2x * [2x + 1]) f(x) = 1 + 2*3 + 4*5 + ... (4x2 + 2x]) f(x) = 1 + ∑(4x2 + 2x) So you can do it with a simple for loop: tally := 1; FOR count := 1 TO maximum DO BEGIN WRITELN(tally, ', '); tally := tally + count * (4 * count + 2 ); END;
