At 45° angle.
The half maximum range of a projectile is launched at an angle of 15 degree
45 degrees.
45 degrees is the furthest one
A baseball, cannonball, or other projectile launched at a 45° angle above the horizon will achieve maximum horizontal range. A projectile launched straight up will achieve maximum altitude, but you kind of have to watch it and be careful when it returns.
15.42 degrees
The range of projectile is maximum when the angle of projection is 45 Degrees.
The half maximum range of a projectile is launched at an angle of 15 degree
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
45 degrees.
45 degrees is the furthest one
Speed, weight, and shape of the projectile- along with the angle at which the barrel is raised above the horizonatal.
Factors include the angle at which it is fired, the speed of the projectile, its shape (ballistic coefficient) the air pressure and humidity.
A baseball, cannonball, or other projectile launched at a 45° angle above the horizon will achieve maximum horizontal range. A projectile launched straight up will achieve maximum altitude, but you kind of have to watch it and be careful when it returns.
15.42 degrees
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.The range of a projectile on level ground, when air resistance is ignored, isd = v2*sin(2x)/g wherev is the intial velocity of the projectile,x is the angle above the horizontal at which the projectile is launchedandg is the acceleration due to the earth's gravity.This function is a maximum when x = 45 degrees and so d is smaller for other values of x.
Are you asking about the maximum effective range or the maximum range that a 22 short projectile can travel?