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The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25
The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249
→ number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
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Can you find three consecutive natural numbers none of which is divisible by 3?
No. Every third consecutive natural number is divisible by 3.
How many 2-digit or 3-digit numbers can be formed using the digits 134568 and 9 which are diisible by 4?
48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4. → 5 x 8 = 40 three digit numbers are divisible by 4 → 40 + 8 = 48 two or three digit numbers made up of the digits {1, 3, 4, 5, 6, 8, 9} are divisible by 4. If repeats are allowed, there are an extra 2 two digit numbers (44 and 88) and each of the two digit numbers can be preceded by any of the 7 digits, making a total of 7 x 10 + 10 = 80 two and three digits numbers divisible by 4 make up of digits from the given set.
What is the divisibility rule for 9?
If you add up the digits, and the sum is divisible by 9 or a multiple of 9.* * * * *For really big numbers you may need to find the digital root (sum of digits) of the digital root.The divisibility rule for 9 is that the sum of the digits of a number must add up to 9 or a multiple of 9.For example, is 81 divisible by 9? Lets find out! 8+1=9. Then it is divisible by 9.
What are the numbers divisible by three?
If the digits add up to a multiple of three for example: 52039 5+2+0+3+9=19 19 is not divisible by 3 so 52039 is not divisible by 3 --------- 342 3+4+2=9 9 is divisible by 3 so 342 is divisible by 3
How do you know what is divisible by 8?
If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!
How do you know when a number is divisible by 8?
Numbers are divisible by 8 if the number formed by the last three individual digits is evenly divisible by 8. For example, the last three digits of the number 3624 is 624, which is evenly divisible by 8 so 3624 is evenly divisible by 8.
What three consecutive natural numbers are not divisible by three?
0, 1, 2
What are some numbers divisible by 5 and 3 and has three digits?
105, 120, 135 and so on.
Can you find three consecutive natural numbers none of which is divisible by 3?
No. Every third consecutive natural number is divisible by 3.
Is 10000 divisible by three?
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
What are all the two digit numbers that are divisible by both the sum and the product of its digits?
There are three such numbers: 12, 24 and 36.
Is the number two thirds a natural number?
No, since 2 is not divisible by three in the natural numbers.
If the last three digits of a binary numbers are 0 show the corresponding decimal numbers is divisible by 2 to the power 3?
213
How many 2-digit or 3-digit numbers can be formed using the digits 134568 and 9 which are diisible by 4?
48. Assuming no digit can be used more than once, the two digit numbers divisible by 4 are: 16, 36, 48, 56, 64, 68, 84, 96 8 of them. For any number to be divisible by 4, only the last two digits need be divisible by 4; so for three digit numbers, each of the two digit numbers above can be preceded by any of the remaining 5 digits and still be divisible by 4. → 5 x 8 = 40 three digit numbers are divisible by 4 → 40 + 8 = 48 two or three digit numbers made up of the digits {1, 3, 4, 5, 6, 8, 9} are divisible by 4. If repeats are allowed, there are an extra 2 two digit numbers (44 and 88) and each of the two digit numbers can be preceded by any of the 7 digits, making a total of 7 x 10 + 10 = 80 two and three digits numbers divisible by 4 make up of digits from the given set.
How many natural numbers between 1 and 30 are divisible by three?
9
What are some three-digit numbers divisible by 5?
Every three-digit number that ends with a zero or a 5 is divisible by 5.It doesn't matter what the first 2 digits are.
How many numbers are left out from 1 to 40 which are not only divisible by 4 but also has 4 as one of the digits?
Three of them.
