Leaving out equivalent permutations, around 50:
1+2+9
1+3+8
1+4+7
1+5+6
2+2+8
2+3+7
2+4+6
2+5+5
3+3+6
3+4+5
4+4+4
1*2*6
1*3*4
2*2*3
4+9-1
5+9-2
5+8-1
6+9-3
6+8-2
6+7-1
7+9-4
7+8-3
7+7-2
8+9-5
8+8-4
9+9-6
21*6
22*3
2*61
3*41
31*4
0!*3!*2
0!*4!/2
1!*3!*2
1!*4!/2
0!*3!*2!
0!*4!/2!
1!*3!*2!
1!*4!/2!
3!*2/0!
3!*2/1!
3!*2!/0!
3!*2!/1!
4!/(2!*1)
4!/(2!*1!)
4!/(2!*0!)
5!/(5*2)
5!/(5*2!)
19 times10,11 (is 2),12,13,14,15,16,17,18,19,21,31,41,51,61,71,81 and 91
8 of them.
With 123 digits you can make 123 one-digit numbers.
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
16000
about... 25 just take 5 numbers times 5 numbers
12 numbers
Not sure what a "didget" is. It is possible to make 18 5-digit numbers.
11 times
As a digit in other numbers it appears 20 times
8
The digit 3 will be written 20 times.