16000
No digit that is 5 places long is equal to 6 times 2 other than 12.000
To determine how many digit numbers can be formed using the digits 2, 3, 5, 7, and 8, we need to consider the number of digits in the numbers we are forming. For a 1-digit number, we can use any of the 5 digits. For a 2-digit number, we can choose 2 out of the 5 digits and arrange them, giving us (5 \times 4) combinations. We can continue this for 3-digit, 4-digit, and 5-digit numbers, which will yield (5), (20), (60), and (120) respectively. Therefore, the total number of digit numbers is (5 + 20 + 60 + 120 = 205).
To form a four-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digits, you can choose the first digit in 6 ways, the second digit in 5 ways, the third digit in 4 ways, and the fourth digit in 3 ways. Therefore, the total number of four-digit combinations is calculated as (6 \times 5 \times 4 \times 3 = 360). Thus, 360 different four-digit numbers can be formed.
3897
To form a 3-digit even number, the last digit must be an even digit (0, 2, 4, 6, or 8), giving us 5 options for the last digit. The first digit can be any digit from 1 to 9 (9 options), and the second digit can be any digit from 0 to 9 (10 options). Therefore, the total number of 3-digit even numbers is calculated as (9 \times 10 \times 5 = 450).
No digit that is 5 places long is equal to 6 times 2 other than 12.000
To form a four-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digits, you can choose the first digit in 6 ways, the second digit in 5 ways, the third digit in 4 ways, and the fourth digit in 3 ways. Therefore, the total number of four-digit combinations is calculated as (6 \times 5 \times 4 \times 3 = 360). Thus, 360 different four-digit numbers can be formed.
3897
first digit time second digit and second digit times first digit then repeat
How many times does the digit 1 occur in ten place in the numbers from 1 to 1000?
6,561
Numbers between zero and nine are represented by 1-digit numbers -- 8, for example. Numbers between ten and ninety-nine are represented by 2-digit numbers -- 58, for example. Numbers between one hundred and nine-hundred-ninety-nine are represented by 3-digit numbers -- 258, for example.Look at the number 258. The last digit on the right is in the ones' place. The number 258 contains 8 ones.The next digit to the left is in the tens' place. The value of a number in the tens' place is ten times the value of the same number in the ones' place. The number 258, therefore, contains 5 groups of ten.The next number to the left is in the hundreds' place. The value of a number in the hundreds' place is ten times the value of the same number in the tens' place. The number 258, therefore, contains 2 groups of one hundred
10,000
11 times
Well, honey, the digit 3 appears in every odd number that ends in 3, 13, 23, 33, and so on up to 39. So, in the first 40 odd numbers, the digit 3 appears 4 times. Math doesn't have to be a drag, darling!
The digit 3 will be written 20 times.
As a digit in other numbers it appears 20 times