The question is rather confused since a tetracontakaioctagon is a 2-dimensional shape whereas a prism is 3-dimensional.
Moreover, [3-dimensional] polyhedra are generally named according to the number of faces that they have and, apart from the tetrahedron, the number of vertices is indeterminate. A pentahedron (5- faces) can have 4 or 5 vertices.
A prism with 9 faces is a heptagonal prism. That has 14 vertices.
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A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 10 vertices
A prism with an n-sided base will have 2n vertices. A pyramid with an n-sided base will have n + 1 vertices. 6, 4, 8 and 5 vertices respectively.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.
A prism with 9 faces is a heptagonal prism. That has 14 vertices.
24 vertices
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28 We can check this using smaller prisims, with a triangular prism (3-sided) there are 6 vertices. WIth a rectangular prism (4-sided), there are 8 vertices. The number of vertices in a prism is always twice the number of sides.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 16 vertices
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 10 vertices
A prism with an n-sided base will have 2n vertices. A pyramid with an n-sided base will have n + 1 vertices. 6, 4, 8 and 5 vertices respectively.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.
A n-sided (based) prism has: Faces: n + 2 Vertices: 2n Edges: 3n
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges.