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Q: How many ways to rearrange the letters of the word 'CHEESE'?

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We can rearrange the letters in tattoo 60 times.

Banana

4! = 24 ways.

there should be 720 ways !

24 ways

5!/(2!*2!) = 30 ways.

You can arrange the letters in group One hundred and twenty-five different ways.

This is how you do it, there are 7 letters in average so it would be, 7x6x5x4x3x2x1.

The number of permutations of the letters PENCIL is 6 factorial, or 720.

You can rearrange them 120 ways. Five of those ways could be considered English words: satin, stain, saint, antis, Tinas

"Colonialist" has 11 letters, including 3 pairs of matching letters, so the letters can be arranged in: 11! / (2! * 2! * 2!) = 4,989,600 ways.

Make notes that:There are 2 c's in the given word.There are 2 o's in the given word.Since repetition is restricted when rearranging the letters, we need to divide the total number of ways of rearranging the letters by 2!2!. Since there are 9 letters in the word to rearrange, we have 9!. Therefore, there are 9!/(2!2!) ways to rearrange the letters of the word 'chocolate'.

Since you didn't say they had to spell anything there are 720 possibilities.

(5 x 4 x 3 x 2 x 1) = ( 5 ! ) = 120 ways.

there should be 720 ways !

There are 6 different letters. That means you have 6 choices for placing the first letter. Once you have placed that letter, you now have 5 choices for the second letter. So you have 6*5 = 30 options for the first two letters. Continuing this way, you have 6*5*4*3*2*1 = 720 ways to rearrange the 6 letters.

There are 6!/2! = 360 ways.

Three letter words that can be made from the word OLYMPIC are:copcoyicyimpliplopmilmopoilplypoi

There are (4*3)*(6*5*4*3*2*1) = 8640 ways.

6

The letter is the word "small" can be rearranged in 60 different ways.

Using all letters? You have seven different letters, so you can rearrange them in 7! (read: seven factorial) different ways, that is, 1 x 2 x 3 x 4 x 5 x 6 x 7.

If you mean in "how many ways can one rearrange the letters in the word care?" (which is what I'll assume as its posted as a maths question) then the answer is 4! ie 4 factorial ie 4x3x2x1=24.

In the word "function" you have 8 letters. 6 different letters and 2 equal letters.The number of different arrangements that are possible to get are:6!∙8C2 = 720∙(28) = 20 160 different arrangements.

The number of permutations of the letters of the word depends upon the number of letters in the word and the number of repeated letters. Since there are nine letters, if there were no repetitions, the number of ways to rearrange these letters would be 9! or 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1. But don't do the multiplication just yet. To account for the repeated letters, we need to divide by 3! (for the 3 Ns) by 2! (for the 2Es) and by another 2! (for the 2 Ss). This gives a final answer of 15,120 permutations of these letters.