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9! (nine factorial)
However, since the S is repeated 4 times you need to divide that by 16, and since the E is repeated once, you need to divide that by 2. The final result, which is the number of distinctcombinations of the letters POSSESSES is 11340.
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How many ways can you rearrange the letters Eric?
4! = 24 ways.
How many different ways can you rearrange the letters of the word 'chocolate'?
Make notes that:There are 2 c's in the given word.There are 2 o's in the given word.Since repetition is restricted when rearranging the letters, we need to divide the total number of ways of rearranging the letters by 2!2!. Since there are 9 letters in the word to rearrange, we have 9!. Therefore, there are 9!/(2!2!) ways to rearrange the letters of the word 'chocolate'.
How many ways can you rearrange the letters in the word pencil?
To calculate the number of ways the letters in the word "pencil" can be rearranged, we first determine the total number of letters, which is 6. Since there are two repeated letters (the letter 'e'), we divide the total number of letters by the factorial of the number of times each repeated letter appears. This gives us 6! / 2! = 360 ways to rearrange the letters in the word "pencil."
How many ways to rearrange the letters of the word 'CHEESE'?
CHEESE cheese has 6 letters in it. if you have a word with different letters, you do the factorial of the number of letters there are. but you can not do that in this word. since it has 3 E's, then you mut do 6!(factorial) divided by 3! then the answer would be 120
How many ways are there to rearrange the letters in inaneness?
The number of permutations of the letters of the word depends upon the number of letters in the word and the number of repeated letters. Since there are nine letters, if there were no repetitions, the number of ways to rearrange these letters would be 9! or 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1. But don't do the multiplication just yet. To account for the repeated letters, we need to divide by 3! (for the 3 Ns) by 2! (for the 2Es) and by another 2! (for the 2 Ss). This gives a final answer of 15,120 permutations of these letters.
How many ways can you rearrange the letters in tattoo?
We can rearrange the letters in tattoo 60 times.
How many ways can you rearrange the letters in chocolate?
Banana
How many ways can you rearrange the letters in math?
there should be 720 ways !
How many ways can you rearrange the letters Eric?
4! = 24 ways.
How many ways can you rearrange the letters in LEVEL?
5!/(2!*2!) = 30 ways.
How many ways can you rearrange the letters in group?
You can arrange the letters in group One hundred and twenty-five different ways.
How many possible ways are there to rearrange the letters in the word jump?
24 ways
In how many ways can you rearrange the letters of the word SATIN?
You can rearrange them 120 ways. Five of those ways could be considered English words: satin, stain, saint, antis, Tinas
How many ways can you rearrange the letters in the word pencil?
To calculate the number of ways the letters in the word "pencil" can be rearranged, we first determine the total number of letters, which is 6. Since there are two repeated letters (the letter 'e'), we divide the total number of letters by the factorial of the number of times each repeated letter appears. This gives us 6! / 2! = 360 ways to rearrange the letters in the word "pencil."
How many ways can you rearrange average?
This is how you do it, there are 7 letters in average so it would be, 7x6x5x4x3x2x1.
How many different ways can you rearrange the letters of the word 'chocolate'?
Make notes that:There are 2 c's in the given word.There are 2 o's in the given word.Since repetition is restricted when rearranging the letters, we need to divide the total number of ways of rearranging the letters by 2!2!. Since there are 9 letters in the word to rearrange, we have 9!. Therefore, there are 9!/(2!2!) ways to rearrange the letters of the word 'chocolate'.
How many ways can you rearrange the letters in colonialist?
"Colonialist" has 11 letters, including 3 pairs of matching letters, so the letters can be arranged in: 11! / (2! * 2! * 2!) = 4,989,600 ways.
