1st: the size of the box must be identified; most boxes have the size printed on one of the sides. If not then multiply the length by the height by the depth.
if there is a plaster ring on the box add that to the total size of the box.
2nd: the size of each wire must be found at NEC Table 314.16(B) ; for 12 AWG it is 2.25 cubic inches. if size is bigger than #6 AWG then Table 1 Chapter 9.
3ed: for each device installed in the box add two of the wires connected to the device; ie, for and outlet that has 12 AWG wired into it, add 4.5 (2*2.35) cubic inches, for each wire (other than ground) 2.25 cu in. add one 2.25 cu in per all grounds.
IE, 4*4*2.5 square box with a 2 Gang Plaster ring with 1/2 in rise.
(box) 4*4*2.5=40
(ring) 1/2*4*4= 8
total size of the box and ring is 48 Cubic Inches.
what can be fitted int such a box?
two outlets; 2 "devices" * (2 * 2.25) per devices = 9
three 12-2 Romex wires 3 * 2 (conductores per set disregarding ground) * 2.25 = 13.5
two 12-3 Romex wires 3 * 3 (conductores per set disregarding ground) * 2.25 = 20.25
add one 2.25 for all grounds
add one 2.25 for all connecters
9+13.5+13.5 + 2.25 + 2.25= 47.25.
for more details see NEC 314.15
6
No. If you leave some copper wire in a square box it will never come out in a square shape.
It depends on the size of the boxes. If the boxes are one square foot, then you need 1400 of them. This obviously differs with box size.
This depends on the size of the wire and the size of the box. Look in article 370 of the NEC code book under box fill. If you are using a plastic box it will have info printed on the box. If you need a licensed electrician lyou can find an electrical contractor at www.contraxtor.com
You do not use a ground wire in the connection from the meter base to the distribution panel. A bonding wire may be required if the service is using PVC conduit.
picture 4 packs of cards in a square. around that size to the shelf.
17 squares. 1 of size 4x4, 4 of size 3x3, 9 of size 2x2, 16 of size 1x1 Total 30 but that depends on a particular interpretation of the question (16 squares arranged in a 4x4 group). If the 16 are arranged in a row, then they might be regarded as a rectangle and you only have 1 square (the box). If you define the box to be a real 3 dimensional box then the box itself has 6 or 5 squares depending on if it has a lid or not.
180 square feet will fit a room 12 x 15.
It all depends on the size of the box!!!! It all depends on the size of the box!!!!
The answer depends on what type of access you have to the junction box. The wire external to the box may have some slack that can be brought into the box. If everything is tight you will probably have to install one or more additional junction boxes or rerun wire from electric panel. As an example assume that the short wire has no external slack, but you can install a new junction box near the other box and in the path of the short wire. 1. Pull the short wire from existing junction box. 2. Install new box in path of short wire so more slack will be available in the additional junction box; and pull wire into new box. 3. Run a wire of the same size from new to old box and re-splice any connections for original short wire or new connections; and connect this new wire to the original short wire in the new box. Make sure you follow all code requirements for your locale.
Look on the box or bag that the wire nuts came in, there you will find all of the combinations of wire sizes that can be connected together under one nut.
10/3 wire with 30 amp double pole breaker from panel box to water heater.