Answer: 170ml of 5% acid must be added to
30 ml of 25% to get 200ml of 8% acid
Let x = wt of 5% acidy = wt of 25% acid
Equations:
x + y = 200ml ----equatio
n 1
0.05x + 0.25y = 0.08(200)
0.05x + 0.25y = 16 -----equatio
n 2
multiply equatio
n 2 by 100
5x + 25y = 1600 -------equatio
n 3
multiply equatio
n 1 by -5
-5x -5y = -1000 ------- equatio
n 4
elimi
nate
equatio
ns 3 a
nd 4
5x + 25y = 1600
-5x - 5y = -1000
=====================
0 +20y = 600
divide by 20
y = 30
substitute y = 30 i
n equatio
n 1
x + 30 = 200
x = 200 - 30
x = 170
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
x=45
18% of 330 = 59.4 So there are 59.3ml of pure acid in 330ml of 18% acid solution.
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
x = amount of acid to add. y = final volume. 5 gal + x = y original amount of acid + acid added = final amount of acid (5 X .2) + x = O.5y Subtract the second equation from the first one. 5 - 1 + x - x = y - 0.5y 4 = 0.5y 8 = y Therefore the final volume is 8 gallons. 5 gal + x = 8 x = 3 gal. the amount of pure acid to add. Check the answer 5 X .2 = 1 gal of acid in original solution. 3 gallons added = 4 gallons total acid in solution. 4 gallons total acid in final solution of 8 gallons total solution = 50% acid.
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
1200
6 ounces
600ml.
128 liters
there is 5 percent acid in bleach
you tell me
144liters
10 liters
x=45
256 liters
48 ml