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How much 5 percent acid must be added to 25 percent acid to get 200ml of acid 8 percent acid?
Wiki User
∙ 11y ago
Answer: 170ml of 5% acid must be added to
30 ml of 25% to get 200ml of 8% acid
Let x = wt of 5% acidy = wt of 25% acid
Equations:
x + y = 200ml ----equatio
n 1
0.05x + 0.25y = 0.08(200)
0.05x + 0.25y = 16 -----equatio
n 2
multiply equatio
n 2 by 100
5x + 25y = 1600 -------equatio
n 3
multiply equatio
n 1 by -5
-5x -5y = -1000 ------- equatio
n 4
elimi
nate
equatio
ns 3 a
nd 4
5x + 25y = 1600
-5x - 5y = -1000
=====================
0 +20y = 600
divide by 20
y = 30
substitute y = 30 i
n equatio
n 1
x + 30 = 200
x = 200 - 30
x = 170
Wiki User
∙ 11y ago
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How much 5 percent acid must be added to 25 percent acid to get 200 ml of 8 percent acid?
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
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How much 5 percent acid must be added to 25 percent acid to get 200 ml of 8 percent acid?
Answer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solutionLet x = 5% acid solutiony = 25% acid solution Equations:x + y = 200mL ----equation (1)0.05x + 0.25y = 0.08 * 2000.05x + 0.25y = 16multiplying by 1005x + 25y = 1600 ----equation (2)eliminating equations (1) and (2)-5(x + y = 200)-5-5x -5y = -10005x +25y = 1600=========20y = 600y=30substitute x=30 to equation (1)x + 30 = 200x = 200 - 30x = 170thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
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