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How much 5 percent acid must be added to 25 percent acid to get 200 ml of 8 percent acid?
A
nswer:170mL of 5% acid solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
Let x = 5% acid solution
y = 25% acid solutionEquations:
x + y = 200mL ----equation (1)
0.05x + 0.25y = 0.08 * 200
0.05x + 0.25y = 16
multiplying by 100
5x + 25y = 1600 ----equation (2)
eliminating equations (1) and (2)
-5(x + y = 200)-5
-5x -5y = -1000
5x +25y = 1600
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20y = 600
y=30
substitute x=30 to equation (1)
x + 30 = 200
x = 200 - 30
x = 170
thus 170mL of 5% solution and 30mL of 25% solution must be mixed to produce 200mL of a 8% acid solution
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