If "6 inch" is the inside diameter of the hose, then
Volume = (pi) (radius)2 (length) = (pi) (3)2 (1,200) = 33,929.2 cubic inches = 146.88 gallons (rounded)
Weight of 50ft section of 3 inch hose with water in it?
109 lbs with no water
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.
A 2.5 inch fire hose has a capacity of approximately 60 gallons per 100 ft. Therefore, a 50 ft hose would hold around 30 gallons of water.
It is an accepted fire service understanding that 5" Large Diameter Hose (LDH) will hold 1 gallon/ft. On average a 100' section of 5" empty weighs 110 lbs. With water weighing 8.33 lbs/gal. a 100' section of LDH filled with water will weigh approximately 944 lbs.
1200gpm
300 GPM
A standard fire hose is 50 feet long. A hose this length with a 2-inch radius grants about 4.36 cubic feet. This volume holds 32 gallons of water.
you need more info than that. you will need to provide the length of the hose and the inside diameter of the hose to calculate the amount of water it will hold
Roughly 1 gallon for every 18 inches of hose.
The formula for volume of a pipe (or hose) is V =(PI/4) * D2 * L Assuming that each section of hose is the same length, we can find the volume for each diameter hose. V2-inch = (PI/4)*(2 in)2*L = PI*L V1-inch = (PI/4)*(1in)2*L = 0.25PI*L So the ratio of volumes of 2 inch to 1 inch hose is : V2-inch / V1-inch = PI*L / 0.25PI*L = 4:1
If it's full of water, then the water in it weighs about 106.5 pounds. I have no way of knowing what the empty hose weighs by itself. Whatever it is, you'll need to add that to 106.5 pounds.