1200gpm
The critical velocity for a 3-inch hose depends on the fluid flowing through it. In general, critical velocity is the velocity at which the flow changes from laminar to turbulent. It can be calculated using the Reynolds number for the specific fluid and hose diameter.
Difficult to say. Hydraulic resistance is proportional to diameter as well as length and velocity. Water moving very slowly in a short length of either type of hose would have negligible resistance. The more likely answer you want is that high-velocity water in a garden hose would experience MUCH more resistance (friction loss) than that in any fire hose of larger diameter. The actual numbers will depend upon specific friction-loss factors, including the type and size of hose and the gallons per minute. For example, the friction loss coefficient in a 1.5-inch fire hose (24) is more than ten times what it would be in a 2.5-inch hose (2.0) and 100 times that of a 4-inch hose (0.2).
Weight of 50ft section of 3 inch hose with water in it?
A standard fire hose is 50 feet long. A hose this length with a 2-inch radius grants about 4.36 cubic feet. This volume holds 32 gallons of water.
A 2.5 inch fire hose has a capacity of approximately 60 gallons per 100 ft. Therefore, a 50 ft hose would hold around 30 gallons of water.
109 lbs with no water
100 pounds with couplings, 68 without.
All else being equal, a 2-inch hose carries 4 times the volume as a 1-inch hose.
NFPA 1901, Standard for Automotive Fire Apparatus - Requires pumpers to carry: * 15 feet of large soft sleeve hose or 20 feet of hard suction hose * 1200 feet of 2 ½ inch or larger supply hose * 400 feet of 1 ½ , 1 ¾, or 2 inch attack hose
If "6 inch" is the inside diameter of the hose, thenVolume = (pi) (radius)2 (length) = (pi) (3)2 (1,200) = 33,929.2 cubic inches = 146.88 gallons (rounded)
That section of hose holds 25.5 gallons of water when it's full, which weighs about 213 pounds. To that, add the weight of the empty hose, which I don't know.