538J
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
heat will flow from the iron to the water until both are the same temperature
Temperature isn't governed by weight so both can have the same temperature. Do you mean which has a higher melting point? That's iron as silver melts at a lower temperature.
1 cubic foot of iron, at room temperature would weigh approx 2190 newtons.
The density of iron (at room temperature) is approx 7.87 grams/cm3. Therefore, volume of 63.6 grams = 8.08 cm3
1935 J
Q = 3 000 . 0,444 . ΔT (joules)ΔT is the difference of temperature.
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
38 cal
(Explanation): remember to convert the 2kg to grams, then multiply in this equation Q=(2000)(0.45)(3) to get Q=2700J
yes
It means that it takes more energy to produce the same increase in temperature in the same amount. For example it takes more energy to raise the temperature of 1 gram of water by 1 degree than it does to do the same with 1 gram of iron. Therefore water has a higher specific heat.
A substance's molar specific heat capacity is the amount of energy required to raise one mole of that substance 1 degree Celsius.For water, this is exactly one calorie, assuming the state of the water does not change. Otherwise, it depends on the substance, and the substance's current temperature and state.for apex its latent
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
Iron naturally exists in solid state and heat is required for its liquifaction so liquid iron has high thermal energy.
0.11cal/g degrees C