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q( in Joules ) = mass * specific heat * change in temperature [ convert temps--Tf = Tc(1.80) + 32 ]

q = (40 g)(0.90 J/gC)(61.1o C - 22.8o C)

= 1.4 X 103 Joules

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Q: How much heat in joules to heat a 40 g sample of aluminum from 73 degrees f to 142 degrees f?
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