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How much heat in joules to heat a 40 g sample of aluminum from 73 degrees f to 142 degrees f?
Wiki User
∙ 11y ago
q( in Joules ) = mass * specific heat * change in temperature [ convert temps--Tf = Tc(1.80) + 32 ]
q = (40 g)(0.90 J/gC)(61.1o C - 22.8o C)
= 1.4 X 103 Joules
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Wiki User
∙ 11y ago
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How many joules of energy are required to raise the temperature of 20g of aluminum from 10 degrees C to 15 degrees C?
Heat energy Q = mass x specific heat capacity x temperature change. Q = m*c*delta T Q = Joules m = kg c (aluminum) = 895.8 J/kg delta T = degr.C temp. change Answer: Q = (20/1000) x 895.8 x 5 = 89.58 Joules (Specific heat capacity of aluminum is obtained by multiplying its specific heat of 0.214 with c of water which is 4186 J/kg = 0.214 x 4186 = 895.8 J/kg).
How much heat is released when 12.4 g of steam at 100 degrees celsius condenses to water at 100 degrees celsius?
The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.
Is temp or heat measured in degrees?
If you want to be pedantic, scientists measure temperature in kelvins, not degrees. Heat is energy and is measured in energy units, like joules.
How many joules are absorbed by the water with a mass of 8 kg in order to raise the temperature from 20 degrees to 70 degrees?
q(joules) = mass * specific heat * change in temperature ( 8 kg = 8000 grams ) q = (8000 grams H2O)(4.180 J/gC)(70o C - 20o C) = 1.7 X 106 joules ============
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?
Approx 4974 Joules.
How much heat energy is needed to raise the temperature of a 055kg sample of aluminum from 22.4 degrees celsius to 94.6 degrees celsius?
The heat energy required can be calculated using the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the aluminum (0.055 kg), c is the specific heat capacity of aluminum (900 J/kg°C), and ΔT is the change in temperature (94.6°C - 22.4°C = 72.2°C). Plugging in the values, we get Q = 0.055 kg * 900 J/kg°C * 72.2°C = 3582.7 J. Hence, 3582.7 Joules of heat energy is needed to raise the temperature of the aluminum sample.
Is heat energy measured in units of joules degrees Celsius and in degrees Fahrenheit?
Heat energy is typically measured in joules (J) or calories (cal). Degrees Celsius and degrees Fahrenheit are units of temperature, not energy.
A particular sample of iron requires 562 Joules to raise its temperature from 25 degreee Celsius to 50 degrees Celsius. What must be the mass of the sample of iron?
To find the mass of the iron sample, you need to know the specific heat capacity of iron. Given that the heat energy required to raise the temperature is 562 Joules, you can use the formula: heat energy = mass x specific heat capacity x temperature change. With the specific heat capacity of iron (0.45 J/g°C), you can calculate the mass of the iron sample.
Is heat is measured in degrees Celsius?
No, heat is not measured in degrees Celsius. Heat is a form of energy and is typically measured in joules or calories. Temperature, on the other hand, is measured in degrees Celsius.
How many joules of energy are required to raise the temperature of 20g of aluminum from 10 degrees C to 15 degrees C?
Heat energy Q = mass x specific heat capacity x temperature change. Q = m*c*delta T Q = Joules m = kg c (aluminum) = 895.8 J/kg delta T = degr.C temp. change Answer: Q = (20/1000) x 895.8 x 5 = 89.58 Joules (Specific heat capacity of aluminum is obtained by multiplying its specific heat of 0.214 with c of water which is 4186 J/kg = 0.214 x 4186 = 895.8 J/kg).
How much eat in calories is required to heat a 43 g sample of aluminum from 72 F to 145F?
How much heat (in calories) is required to heat a 43 g sample of aluminum from 72 F to 145F
How many joules would be required to heat 0.5kg of aluminum?
The specific heat capacity of aluminum is 0.897 J/g°C. To calculate the energy required to heat 0.5kg of aluminum by a certain temperature change, you would use the formula: Energy = mass x specific heat capacity x temperature change If you have the temperature change, you can plug the values into the formula to find the total energy in joules.
How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?
46 calories (or 192, 464 joules) for each Celsius degree.
How much heat is released when 12.4 g of steam at 100 degrees celsius condenses to water at 100 degrees celsius?
The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.
How much joules does it take to heat water to 100 degrees?
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
How much energy is required to raise the temperature of 0.2kg of aluminum for 15 degrees celsius to 18 degrees celsius?
The specific heat capacity of aluminum is 0.9 J/g°C. To calculate the energy required to raise the temperature of 0.2kg of aluminum by 3 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. Substituting the values into the formula, Energy = 0.2kg x 0.9 J/g°C x 3°C = 0.54 Joules.
