1 calorie is needed to raise 1 g of water 1 °C.
350 * 22 = 7700 calories ■
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
23joules
Specific temperature is an amount of heat per unit mass required to raise the temperature by one degree Celsius.
The answer is 4,18 joule.
Do you mean how can you boil at different temperatures? You can add lots of salt to the boiling water to raise the temperature. This isn't very effective. The best method is to pressurize the pot (pressure cooker) this will raise the temperature quite a bit, up to 250 degrees at the highest pressure allowed by a pressure cooker. Do you mean what are the different temperature scales and boiling points? water boils at 212 degrees F or 100 degrees C
700
15480.80
69
q=mass * Cs * delta T = 0.25kg * 4.18 * (85-10) =78J
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
314j
3.50 J
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
1935 J (apex)
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
The number of calories required will depend on the mass of water which is to be heated.