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How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
Wiki User
∙ 12y ago
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
Wiki User
∙ 12y ago
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How much heat is required to raise the temperature of 350 grams of water from 22 degrees C?
1 calorie is needed to raise 1 g of water 1 °C. 350 * 22 = 7700 calories ■
What is the quantity of heat in joules or calories required to raise the temperature of 1 gram of a substance 1C?
specific heat(; your welcome!
How many calories are required to raise the temperature of 1 g of water by 5drgress c?
1 Calorie is equal to 1000 calories one is a big C the other is a small c and 1 Calorie is needed to raise 1gram of water; 1 Degree C* so your answer is 5 Calories or 5000calories
) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
How many SI calories does it take to raise one liter if water 6 degrees Celsius?
6 Calories
What is the total number of calories of heat needed to raise to raise the temperature of the liquid water from 20 degrees Celsius to 30 degrees Celsius?
The number of calories required will depend on the mass of water which is to be heated.
How much heat is required to raise the temperature of 350 grams of water from 22 degrees C?
1 calorie is needed to raise 1 g of water 1 °C. 350 * 22 = 7700 calories ■
How many calories are required to raise 8 grams of water 7 degrees Celsius?
700
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How many calories are needed to raise the temperature of 10 g of water from 25 C to 35 C?
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
How many joules of energy are required to raise the temperature of 74g of water from 20 degrees to 70 degrees celsius?
15480.80
How much heat is required to raise the temperature of 250 grams of water from 10 degrees to 85 degrees celsius?
q=mass * Cs * delta T = 0.25kg * 4.18 * (85-10) =78J
How much energy is required to raise 21kg of water by 2 degrees Celsius?
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
How were calories were made?
calories were never "made." they are simply the amount of energy required to raise the temperature one gram of water one degree celsius.
How much heat is required to raise the temperature of 3.5 grams of water from 12 degrees Celsius to 35 degrees Celsius answer in calories?
80.5 calories 35-12=23 23*3.5=80.5 1c raises 1 gr. h2o 1degree centigrade Here is the formula, it should help a lot:Total Number of Calories = (Specific Heat of Water) ×(Mass of Water) × (Absolute Temperature Change)
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories are required to raise the temperature of a 35.0g sample of iron from 25 C to 35 C?
38 cal
