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q (amt of heat) = mass * specific heat * temp. difference

The specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oC

q = (105 grams)*(1.00 cal/goC)*(40oC)

= 4,200 calories

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Q: How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
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