Imagine the end of the pipe as a circle. If r is radius then area is pi (r squared). So volume is,
Pi multiplied by r squared and multiplied by the length. Make sure the radius and length are in the same units e.g. inches.
so if 0.5 is diameter in inches then radius is half that 0.25.
so r squared is 0.0625 inches2
length in inches is 12 x 250 i.e. 3000 inches.
So answer is pi(3.14.......) x 0.0625 x 3000
= pi x 187.5 cubic inches.
n.b. 1 cubic foot is 12 x12 x12 = 1728 cubic inches. if you want to convert to cubic feet.
It depends on how long the pool is.
23*27*2 cubic feet = 1242 cubic feet.
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A cylinder with these dimensions will hold up to 13.06 gallons of water.
Google volume of a cylinder. once you have the volume, plug in the density of water to get the mass.
(21 x 18 x 9) = 3,402 cubic feet = 126 cubic yards = about 25,448.73 gallons
About 11.3 feet of 3" pipe can hold 5 gallons of water.
The capacity of a 25 ft hose with a diameter of 3 inches is 1.23 cubic feet. That is the maximum volume of water in the hose: there need not be any!
785.375 cubic feet of water.
40 to 50 feet
It is 2,178,000 cubic feet.
The volume enclosed by the tank is equivalent to 3,590.65 gallons (rounded). We have no way of knowing how much water may be in it, or whether it's utterly empty.