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How much work must be done on a 5 kg skateboard to increase its speed from 2 m per s to 10 m per s?
Wiki User
∙ 12y ago
Kinetic energy = 1/2 M V2
At 2 m/s, the board's KE is [ (1/2) (5) (2)2 ] = 10 joules.
At 10 m/s, the board's KE is [ (1/2) (5) (10)2 ] = 250 joules.
The difference is 240 joules, which is the work you have to put into it
to give it the additional kinetic energy.
Wiki User
∙ 12y ago
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