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What else can I help you with?
When an object moves into 5 second zone you must modify your speed?
No, not if you are walking!
What sre the measurements for average speed?
to measure the average speed of a car for instince you must use the following formula SPEED= distance divided by time
How can you identify a proportional linear relationship?
When either of the two variables is zero, the other must be zero. Also, every increase in one variable by some fixed amount must be accompanied by an increase in the other by the same amount each time. The two sets of increases may be different, though.Alternatively, the graph of the two variables must be a straight line in the first quadrant and must pass through the origin.
Which factor must increase to give a machine a mechanical advantage greater than 1?
output force (:
What must be done to a normal curve to make it into a standard normal distribution curve?
The mean must be 0 and the standard deviation must be 1. Use the formula: z = (x - mu)/sigma
How much work must be done on a 5-kg snowboard to increase its speed from 2 m s to 4 m s?
30 J
How much work must be done on a 20-kg go-cart to increase its speed from 5 m/s to 10 m/s?
750 j
How much work must be done on a 10-kg bicycle to increase its speed from 5 m s to 10 m s?
375 Js (((((((((((: this is the right answer
How much work must be done on a kg sled to increase its speed from 10ms to 15 ms?
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
How much work must be done on a 10kg bicycle to increase its speed from 2 M's to 3 M's?
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.
How much work must be done on a 24kg shopping cart to increase its speed from 1 ms to 4 ms?
D. 750 j
How much work must be done on a 24 kg shopping cart to increase its speed from 1 ms to 4ms?
Work done = Increase in kinetic energy SO W = (1/2) m (v22 - v12) So W = 12 x 5 x 3 = 180 J
How much work must be done on a 10-kg snowboard to increase its speed from 2ms to 4 ms 100 J.?
The work done on the snowboard to increase its speed is 100 Joules. This work-energy theorem is based on the change in kinetic energy, given by the equation: work = change in kinetic energy. In this case, the snowboard has a mass of 10 kg and the speed increases from 2 m/s to 4 m/s.
How much work must be done on a 10-kg snowboard to increase its speed from 4 ms to 6 ms?
225000 J
How much work must be done on a 24-kg shopping cart to increase its speed from 1 ms to 4 ms?
Probably less then solving this question or since F=ma 72N. The N stands for Nitwick.
How much must be done for a 100-kg car to increase its speed from 1ms to 2ms?
To increase the speed of the car from 1 m/s to 2 m/s, you must apply a force using Newton's second law: Force = mass x acceleration. The force required will depend on the time over which you wish to achieve this acceleration, as accelerating too quickly may require a larger force.
How much work must be done on a 5 kg snowboard to increase its speed from 2 ms to 4 ms?
The work done on the snowboard is calculated as the change in kinetic energy. The formula for kinetic energy is KE = 0.5 * mass * velocity^2. By calculating the initial and final kinetic energies, the work done would be the difference between the two. In this case, the work done on the snowboard is 60J.
