It depends on the angle of the sun. The height of the tree is equal to the lenght of its shadow times the cotangent (or divided by the tangent) of the sun's angle above the horizon.
It works out as 3.75 feet
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Assuming that you are not using angles, but only ratios I have the following:Your answer is 30 ftCalculations:5 ft : 3f & 4 in (40in)20 * 12 = 240 in240 / 40 = 66 * 5 = 30 ft
20/16 = h/12;Cross multiply: 16 x h = 20 x 12h = 20 x 12/16 = 240/16 = 15 in
8 feet and 5 feet 4 inches are in a ratio of 3 to 2 so therefore the smaller shadow is 2 feet in length
Yes. An inch is a twelfth of a foot. As there are 12 inches to a foot.
1 foot = 12 inches1 foot-pound = 12 inch-pounds
a foot
125 inches = 10.4167 feet 125 inch-pounds = 10.4167 foot-pounds
square feet
1 foot = 12 inches(1 foot) pound = (12 inch) pounds(18 foot) pounds = (18 x 12) = 216 inch pounds
First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in