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8 feet and 5 feet 4 inches are in a ratio of 3 to 2 so therefore the smaller shadow is 2 feet in length

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It is 2 feet long.

Q: How long is the shadow of a 5 feet 4 inch person if a 8 foot cast a 3 foot shadow?

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Divisibles, the 6 foot man would cast a shadow 2 feet long.

Using trigonometry its height is 12 feet

It works out as 30 feet in height

17.45 feet.

10.'384615' (recurring decimals) feet

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Divisibles, the 6 foot man would cast a shadow 2 feet long.

Using trigonometry its height is 12 feet

It works out as 30 feet in height

27.3 feet

17.45 feet.

To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.

Designate the unknown shadow length by s. Shadows cast at the same time and place are proportional to the height of the object casing the shadow. Therefore: 4/6 = s/21, or s = [4(21)]/6 = 14 feet.

10.'384615' (recurring decimals) feet

The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.

The tree was 20 feet tall.

140*10/6 = 233.33... ft or 233 ft 4 inches. Except at that distance, the end of the shadow would be too diffuse to measure accurately.

We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.