30
34 = 81 so x is 4
8 1/3 = ab^-1, 1.8 =ab^2
y = 2(2/3^x -4) y intercept is when x = 0 anything to zero power is 1 y = 2(1-4) = -6
x2 - 7x = 0The left side is the product of x(x-7).The equation is true if either factor is zero.So the equation has 2 solutions:1). X = 02). X = 7
ex = x3 This has two solutions: x = 4.5364... and x = 1.85718... Plot the graph of each and you can see the intersections.
13
30
34 = 81 so x is 4
You can solve for resistance using the formula ( R = \frac{V^2}{P} ), where R is the resistance, V is the voltage, and P is the power. By rearranging the formula, you can solve for resistance by dividing the square of the voltage by the power.
Not if you want REAL solutions: y=4x^4 +2x^2 +3 t=x^2 therefore y=4t^2 +2t +3 Use discriminant: b^2-4ac=4-48=-44 this means there will be no REAL solutions (but there will be COMPLEX solutions-message me if you need this bit explained)
8 1/3 = ab^-1, 1.8 =ab^2
z4-9=0 z4=9
For the equation of any graph. The graph intercepts the y-axis, when x is zero, so in the equation, substitute x=0, and solve for y. To find the x-intercept, this is when y is zero, so substitute y=0, and solve for x. For a parabola, if the highest power of y is the 1st power (no exponent) and the highest power of x is 2, then the parabola opens up or down. The parabola will have 1 y-intercept (usually it is the constant value), and depending on where it is (if it is at the origin, it is also an x-intercept, and the other x-intercept has the same distance as y-intercept has from the axis of symmetry i.e y = a2x + bx), either have 2 x-intercepts, or no interceptions with the x-axis (i.e. y = x2 + c, c ≥ 0 or y = -x2 + c, c ≤ 0). If the highest power of y is 2, and highest power of x is 1, then it opens left or right, and it may have none or 2 y-intercepts, and will have 1 x-intercept. So when you're solving for the one that's a quadratic, if you come up with imaginary or complex roots, that means there is no intercept.
y = 2(2/3^x -4) y intercept is when x = 0 anything to zero power is 1 y = 2(1-4) = -6
x2 - 7x = 0The left side is the product of x(x-7).The equation is true if either factor is zero.So the equation has 2 solutions:1). X = 02). X = 7
E is energy and MC2 is matter used to the second power... now you solve it