This cannot be determined because the number 3 does not exist in base 3; only 1 and 2 do.
1*5^2 + 2*5^1 + 3*5^0
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.
No. 123 is only divisible by: 1, 3, 41, 123.
−4a + 139 = 4a + 123 → −8a = −16 → a = 24a + 123 → 4(2) + 123 = 8 + 123 = 131°
This cannot be determined because the number 3 does not exist in base 3; only 1 and 2 do.
1*5^2 + 2*5^1 + 3*5^0
2 km to 123 m = 2000 m to 123 m = 2000 to 1232 km to 123 m = 2000 m to 123 m = 2000 to 1232 km to 123 m = 2000 m to 123 m = 2000 to 1232 km to 123 m = 2000 m to 123 m = 2000 to 123
123 is not divisible by 2 it is divisible by 3
1252 + 123 = 125
123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.
No. 123 is only divisible by: 1, 3, 41, 123.
39, 41 and 43. or 123/3 -2, 123/3 and 123/3 +2
246 = 123 x 2
−4a + 139 = 4a + 123 → −8a = −16 → a = 24a + 123 → 4(2) + 123 = 8 + 123 = 131°
248
(1/2) x (123/5) = 123/10 = 12.3