cos(α) = sin(90° - α) → cos(16° + θ) = sin(90° - (16° + θ)) = sin(74° - θ) → sin(36° + θ) = cos(16° + θ) → sin((36° + θ) = sin(74° - θ) → 36° + θ = 74° - θ → 2θ = 38° → θ = 19° → θ = 19 °+ 180°n for n= 0, 1, 2, ...
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
Horizontal component = 14 cos(38) = 11.032 lbs (rounded)Vertical component = 14 sin(38) = 8.619 lbs (rounded)
Cosine(38) = Cos(38) = 0.788010753 ( per calculator) or 0.7880 (per Castle's Four Figure Tables).
38/57 = 2/3
i bet shes anorexic cos shes 38 kg
i bet shes anorexic cos shes 38 kg
To find the length of the altitude from a vertex of a triangle given an angle and the length of the side opposite to that angle, you can use the formula: [ h = b \cdot \sin(A) ] where ( h ) is the altitude, ( b ) is the length of the side, and ( A ) is the angle. In this case, ( A = 38^\circ ) and ( b = 14 ). Thus, [ h = 14 \cdot \sin(38^\circ) \approx 14 \cdot 0.6157 \approx 8.63. ] So, the length of the altitude is approximately 8.63 units.
38.00
Find the cosine of 38 degrees and then find its reciprocal.
You can find 38 percent of 22 with the expression 22*38/100
Oh honey, you're throwing some trigonometry at me? Alright, buckle up. The sum of tan20tan32 plus tan32tan38 plus tan38tan20 is equal to 1. Just plug in those values and watch the magic happen. Math can be sassy too, you know.