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cos(α) = sin(90° - α)

→ cos(16° + θ) = sin(90° - (16° + θ)) = sin(74° - θ)

→ sin(36° + θ) = cos(16° + θ)

→ sin((36° + θ) = sin(74° - θ)

→ 36° + θ = 74° - θ

→ 2θ = 38°

→ θ = 19°

→ θ = 19 °+ 180°n for n= 0, 1, 2, ...

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7y ago
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7y ago

Theta = 19 degrees.

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Q: If sin(36 plus theta) cos(16 plus theta) find theta?
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