102
102÷46 = 2 remainder 10
2 - x > 3x + 102 - x + x > 3x + x + 102 > 4x + 102 - 10 > 4x + 10 - 10-8 > 4x-8/4 > 4x/4-2 > x or x < -2
The greatest common factor of 10, 102, and 110 is 2.
The repeated factor of 102 is 10.
First write down the problem neatly using the below format: 102 / 2 = ____ the ____ is where you are going to write the result Now copy dovn the first digit from the left end of the numerator (102) 102 / 2 = ____ 1 Is this number smaller than the divisor (2) yes it is, so we pull down the second digit 102 / 2 = ____ 10 Ten is bigger than 2 so now you divide 2 into 10 2 goes into 10 five times so write 5 as the first digit of the result 102 / 2 = 5___ 10 now multiply the resultdigit by the divisor and write the resulting number under the 10. then subtract that number from 10 102 / 2 = 5___ 10 10 0 pull down the next digit to stand behind the 0 102 / 2 = 5___ 10 10 02 this number is not smaller than the divisor so we divide it by 2 and write the result of dividing as the second digit of the result 102 / 2 = 51__ 10 10 02 again multiply the resultdigit by the divisor and write the resulting number under the 02. then subtract that number from 02 102 /2 = 51__ 10 10 02 2 0 there are no more digits to pull down, so you have finished dividing 102 by 2. The result is 51. This is called long division regards JakobA
(10)2 = (10 x 10) = 100
102=100 so 102 +1=101
6,215/10-2 = 6.215/(1/102) = 6,215 x 102 = 621,500
Yes but it will have a remainder of 2
What is 11010 power by 2 - 1101 power by 2
Ten to the power of 0 is 1 Proof:102/102 = 10(2-2) =100=1