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โˆ™ 2021-09-27 02:26:29
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Q: If a+b+c=66, and ab+ac+cb=1071. Where a, b, and c are all prime factors. Find the value of abc?
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Related questions

Which composite number from six to twenty is closest in value to the sum of its prime factors?

The sum of the prime factors of 6 is closest in value to the composite number 6.


What is the value of 13?

13 is a prime number whose only factors are itself and one


Is X squared plus 3x -2 prime?

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What is the value of 500?

As a product of its prime factors in exponents it is: 22*53 = 500


What is the prime factors for Y?

It is not possible to answer the question without the numerical value of Y.


What is the value of 41?

The value of 41 is equal to a prime number because it has only two factors which are itself and one.


What is the prime factorization for 40y?

That depends on the value of y but 40 as a product of its prime factors is 2*2*2*5 or as 23*5


What is the smallest value of k when 882k is a cube?

Factor the number 882, until you get prime factors. See what prime factors are missing to complete a cube (each prime number has to be to the power 3, 6, etc.). Multiply those missing factors, to get "k".


What is the prime numbers for 374?

To find the prime factors of any number then divide the number by prime numbers of increasing value. When a prime number wholly divides the original number repeat the process with the same prime number but each time with the new quotient until complete division does not occur. Repeat with a prime number of higher value until the final quotient is 1. Using this process gives the prime factors of 374 as 2, 11 and 17.


What is the value of 1 3?

13 is a prime number because it has only two factors which are itself and one.


What is the value of 2564?

As a product of its prime factors: 2*2*641 = 2564 or as 22*641 = 2564


What is the value of the expression 43?

43 is a prime number because it has only two factors which are itself and one


What is the value of number 5?

5 is a prime number because it has only two factors which are itself and one


What are the prime factorizations of 115?

Prime factorization of 115 is: 5x23 Prime factors are the prime numbers multiplied with each other that together form the original numerical value. Prime numbers are numbers that have no factors besides one and itself. The first prime number is 2, then 3, 5, 7, 11, 13, and so on. Sometimes one may have a number that has multiple same prime numbers for its prime factorization; for example the prime factorization of 256 is 2x2x2x2x2x2x2x2


What is w as a product of its prime factors?

There can be no answer without further information about w.


What are some numbers that have an even number of factors?

One subset is prime numbers, since their factors are only 1 and the number itself. Other than that, there are many ways to end up with an even number of factors. The general equation for the number of factors is (p1+1)(p2+1) ... (p3 + 1) where the p values are the exponents of the prime factors of the number. So, as long as at least one prime factor is represented oddly (i.e., there is only 1, 3, 5... so on factors of that value in the prime factorization), then the number will have an even number of factors.


Algorithm to check prime?

For all positive values in the range 0 to infinity: 1. If the value is less than 2 then it is non-prime. 2. If the value is even, then it is prime if and only if the value is 2 otherwise it is non-prime. 3. For all other values, if the value can be divided by any prime factor in the half-closed range 3 to the integer of the square root of the value plus 1, such that the prime factor is less than the value, then it is non-prime, otherwise it is prime. Note that prime factors are always prime so 2 is therefore a prime factor. But 2 can only be a prime factor of an even number, and we eliminated all even values in step 2. Thus when we reach step 3 we know that the value must be greater than 2 and must be odd. Therefore we only need to check for prime factors greater than 2. The first prime after 2 is 3, therefore we start checking from 3. The end of the range of prime factors is defined as the integer of the square root of the value plus 1. This is because there's no point in testing higher prime factors because if one existed, there must also be a lower prime factor. E.g., 3*5 is 15 but so is 5*3. If 3 is a factor then we can stop checking. If the value were 17, then 3 would not be a factor. But the next prime factor is 5 which is greater than the square root of 17. If a higher factor than 5 existed then it follows that 3 would also be a factor. So if there are no factors below the square root there can be no factors above the square root. The square root itself could be a factor (as is the case with 25), thus we add 1 to create a half-closed range. That is, the start of the range is 3 and all potential factors must be greater than or equal to 3 but must be less than the upper bound. Checking if a value is less than another is quicker than checking if it is less than or equal to another, so the overhead of adding 1 to the upper bound saves time when there are two or more potential factors to test, which in the majority of cases there will be. If the upper bound is less than or equal to 3, then there can be no prime factors. If the value were 3 then the range of prime factors would be 3 to 2 and 2 is less than 3 so there are no prime factors therefore 3 is prime. For values 5 and 7, the range becomes 3 to 3. 3 is not less than 3 so there are no prime factors thus 5 and 7 are prime. For all odd values greater than 7, the range becomes valid. Thus a value of 9 creates a range of 3 to 4. 3 is a prime factor of 9 thus 9 is not prime. We can stop checking as soon as we find a prime factor. For 11 and 13, the range is also 3 to 4. 3 is not a prime factor so we move onto the next prime factor. The simplest way to find the next prime factor is to add 2, because all prime factors must be odd. So the next prime factor is 5. But 5 is not less than 4, the upper bound, so neither 11 or 13 have any prime factors and are therefore odd. For 15, the range is also 3 to 4 but 3 is a prime factor of 15 so 15 is not prime. For 17 and 19, the range is now 3 to 5. 3 is not a factor and 5 (the next prime) is not less than 5 (the upper bound), so 17 and 19 are prime. For 21 (range 3 to 5), 3 is a factor so 21 is not prime. For 23 (range 3 to 5), 3 is not a factor so 23 is prime. For 25 (range 3 to 6), 3 is not a factor but 5 is, so 25 not prime. For 27 (range 3 to 6), 3 is a factor so 27 is not prime. For 29 (range 3 to 6), neither 3 nor 5 is a factor so 29 is prime. And so on...


How do you express the prime factorization using exponents?

When prime factorization reveals more than one multiplicand or multiplier having the same value, group those prime factors together exponentially. For example, the prime factorization of 288 is 2x2x2x2x2x3x3, which is 25x32 in exponential form.


Is 4x2 9 prime?

4x^2 + 9 is a prime algebraic expression. Its numerical value may be prime of not - depending on the value of x.For x = 1, the value of the expression is 13 - a prime whereasfor x = 2, the value of the expression is 25 - not a prime.


What is the value of 7 3?

7 and 3 are two prime numbers that add up to 10 If you meant 73 then that is also a prime number because it has only two factors which are itself and one.


What whole number less than 1000000 has the most factors?

If you're not concerned about the factors being distinct (ie. prime factors), then the number in question will simply be the largest power of two that is less than 1000000. That would be 219, or 524288, which has 19 factors, all of them two. If on the other hand you're looking for distinct prime factors, then you can work this out by multiplying a series of prime numbers until the next value exceeds 1000000. That would give you 2 * 3 * 5 * 7 * 11 * 13 * 17 = 510510, leaving you with 7 unique factors.


If the number 360 is written as a product of its prime factors in the form a3 plus b2c what is the numerical value of a plus b plus c?

10


How do you write a C program to test if a number is prime?

Use the following functions to test if a value is prime or not (to test negative values, use the absolute value): // helper functions (test the state of LSB to determine if value is odd or even) bool is_even (const unsigned value) {return (value&0x1)==0x0; } bool is_odd (const unsigned value) {return (value&0x1)==0x1; } bool is_prime (const unsigned value) { if (value<2) return false; // 0 and 1 are non-prime if (is_even(value)) return value==2; // 2 is the only even prime // Test all odd numbers from 3 to the square root of value, see if any are factors unsigned number; const unsigned max; max=sqrt (value); for (number=3; number<=max; number+=2) { if ((value%number)==0) return false; // number is a factor, value is non-prime } return true; // value is prime -- it has only 2 factors, 1 and itself };


How to write an algorithm to generate first ten prime numbers?

bool is_prime (unsigned num) { if (num<2) return false; // 2 is the first prime if ((num%2)==0) return num==2; // 2 is the only even prime unsigned max_div {(unsigned) sqrt (num) + 1}; for (unsigned div=3; div<max_div; div+=2) { // test all odd divisors if ((num%div)==0) return false; // div is a factor of num, so num is not prime } return true; // if we get this far, num has no factors so it is prime } int main () { using namespace std; unsigned count = 0; unsigned num = 0; while (count<10) { if (is_prime (num)) { cout << num << endl; ++count; ++num; } }


What are all the negative prime numbers?

A negative number is prime if and only if its absolute value is prime.