13 is a Prime number because it has only two factors which are itself and one.
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To find the value of (3y^2 + 2) when (y = -1), substitute (-1) for (y): [ 3(-1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5. ] Thus, the value is (5).
3
6-7+(-3) = -1 +(-3) = -1 -3 = -4
3 * 3 + 1 = 10
1.639 '1' : units Decimal point '6' ; Tenths '3' ; Hundredths '9' ; Thousandths. NB Note the suffix '---ths' on the decimal values.