13 is a Prime number because it has only two factors which are itself and one.
To find the value of (3y^2 + 2) when (y = -1), substitute (-1) for (y): [ 3(-1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5. ] Thus, the value is (5).
The absolute value of one and one third, which can be expressed as (1 \frac{1}{3}) or (\frac{4}{3}), is simply its positive value. Since absolute value measures distance from zero on the number line, the absolute value of (1 \frac{1}{3}) is (\frac{4}{3}) or approximately 1.33. Therefore, the absolute value of one and one third is (\frac{4}{3}).
3
6-7+(-3) = -1 +(-3) = -1 -3 = -4
3 * 3 + 1 = 10
To convert 3 times the value to 1 time the value, you would divide by 3.
The value of -3 is -3. The value of x has no bearing on that!
1 + 3 = 4
5
no becasue 3 times 1 = 3
To find the value of (3y^2 + 2) when (y = -1), substitute (-1) for (y): [ 3(-1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5. ] Thus, the value is (5).
Multiply the number 3 times its place value. 1/10, 1/100, 1/1000, 1/10000 3x1/10=3/10
The absolute value of one and one third, which can be expressed as (1 \frac{1}{3}) or (\frac{4}{3}), is simply its positive value. Since absolute value measures distance from zero on the number line, the absolute value of (1 \frac{1}{3}) is (\frac{4}{3}) or approximately 1.33. Therefore, the absolute value of one and one third is (\frac{4}{3}).
1. Value exploration 2. Value creation 3. Value delivery.
None of the numbers are underlined. In the number 56123, the 5 has a value of 50000, the 6 has a value of 6000, the 1 has a value of 100, the 2 has a value of 20 and the 3 has a value of 3.
3
One and three: 1×3 = 3 Negative one and negative three: -1×-3 = 3 One and the absolute value of three: 1×|3| = 3 One and the absolute value of negative three: 1×|-3| = 3 The square root of one and three: √1)×3 = 3