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First, 0.01% is not in the fourth sd.

Prob(-4 < Z < 4) is approximately 0.0064 or 0.64% which, when rounded to 0.1% but is, in fact, smaller.

Prob(0 < Z < 5) is approximately 0.000 000 287 = 0.000 028 7%

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Q: If 0.01 percent is in the fourth s.d. what percentage is in the fifth standard deviation from the mean of a normal distribution curve?
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On a normal distribution a score of 100 on the current IQ test with a standard deviation of 15 points would mean you scored higher than what percentage of the population?

50 percent


Scores on the sat exam approximate a normal distribution with ยต equals 500 and sd equals 100 use this distribution to determine the percentage of sat scores that fall above 600?

The answer is about 16% Using the z-score formula(z = (x-u)/sd) the z score is 1. This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.


If a test has a normal distribution with a mean of 400 and a standard deviation of 100 what would be the minimum score for the top 3 percent of students?

(x-400)/100=1.882 x=588.2


If average height for women is normally distributed with a mean of 65 inches and a standard deviation of 2.5 inches then approximately 95 percent of all women should be between what and what inches?

A normal distribution with a mean of 65 and a standard deviation of 2.5 would have 95% of the population being between 60 and 70, i.e. +/- two standard deviations.


If the mean is 1050 and the standard deviation is 218 what is the conpsumption level separating the bottom 45 percent from the top 55 percent?

The answer will depend on what the distribution is! And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.

Related questions

What percent of the scores in a normal distribution will fall within one standard deviation?

It is 68.3%


On a normal distribution a score of 100 on the current IQ test with a standard deviation of 15 points would mean you scored higher than what percentage of the population?

50 percent


Is the middle spread that is the middle 50 percent of the normal distribution is equal to one standard deviation?

false


What are importance of mean and standard deviation in the use of normal distribution?

For data sets having a normal distribution, the following properties depend on the mean and the standard deviation. This is known as the Empirical rule. About 68% of all values fall within 1 standard deviation of the mean About 95% of all values fall within 2 standard deviation of the mean About 99.7% of all values fall within 3 standard deviation of the mean. So given any value and given the mean and standard deviation, one can say right away where that value is compared to 60, 95 and 99 percent of the other values. The mean of the any distribution is a measure of centrality, but in case of the normal distribution, it is equal to the mode and median of the distribtion. The standard deviation is a measure of data dispersion or variability. In the case of the normal distribution, the mean and the standard deviation are the two parameters of the distribution, therefore they completely define the distribution. See: http://en.wikipedia.org/wiki/Normal_distribution


The mean plus or minus the standard deviation for a normal distribution provides a probability range of what percent?

in a normal distribution, the mean plus or minus one standard deviation covers 68.2% of the data. If you use two standard deviations, then you will cover approx. 95.5%, and three will earn you 99.7% coverage


Scores on the sat exam approximate a normal distribution with ยต equals 500 and sd equals 100 use this distribution to determine the percentage of sat scores that fall above 600?

The answer is about 16% Using the z-score formula(z = (x-u)/sd) the z score is 1. This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.


How do you do percent variation?

Percent variation is the standard deviation divided by the average


What is the middle 95 percent of students who drink five beers with a standard deviation of 01 and a mean of 07?

Not possible to tell you without knowing how many students' there are, and what distribution you wish to use (i.e normal distribution, t-distribution etc...)


What percent of data falls between 1 Standard deviation below and 2 stand deviations above the mean?

The answer will depend on what the distribution is. Non-statisticians often assum that the variable that they are interested in follows the Standard Normal distribution. This assumption must be justified. If that is the case then the answer is 81.9%


If a test has a normal distribution with a mean of 400 and a standard deviation of 100 what would be the minimum score for the top 3 percent of students?

(x-400)/100=1.882 x=588.2


If average height for women is normally distributed with a mean of 65 inches and a standard deviation of 2.5 inches then approximately 95 percent of all women should be between what and what inches?

A normal distribution with a mean of 65 and a standard deviation of 2.5 would have 95% of the population being between 60 and 70, i.e. +/- two standard deviations.


If the mean is 1050 and the standard deviation is 218 what is the conpsumption level separating the bottom 45 percent from the top 55 percent?

The answer will depend on what the distribution is! And since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.