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The answer is about 16%
Using the z-score formula(z = (x-u)/sd) the z score is 1.
This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.
What else can I help you with?
What percentage of scores are between 61 and 82?
To determine the percentage of scores between 61 and 82, you would need to know the distribution of the scores (e.g., normal distribution) and the total number of scores. If the data is normally distributed, you can use the mean and standard deviation to find the percentage of scores in that range using a z-score table. Without specific data, it isn't possible to provide an exact percentage.
What percent of the scores are between 63 and 90?
To determine the percentage of scores between 63 and 90, you would need the complete dataset or a statistical summary (like a frequency distribution or histogram) of the scores. By counting the number of scores within that range and dividing by the total number of scores, then multiplying by 100, you can calculate the percentage. Without specific data, it's impossible to provide an exact percentage.
How do you find the scores at the 60th percentile in a set of 200 scores?
You can't do this without knowing the distribution of scores.
For a normal distribution what z-score value separates the lowest 10 percent of the scores from the rest of the distribution?
-1.28
What kind of graph would you use to show the scores?
When putting the scores in, you use the normal distribution graph, which is the best start.
What percentage of scores are between 61 and 82?
To determine the percentage of scores between 61 and 82, you would need to know the distribution of the scores (e.g., normal distribution) and the total number of scores. If the data is normally distributed, you can use the mean and standard deviation to find the percentage of scores in that range using a z-score table. Without specific data, it isn't possible to provide an exact percentage.
What percent of the scores are between 63 and 90?
To determine the percentage of scores between 63 and 90, you would need the complete dataset or a statistical summary (like a frequency distribution or histogram) of the scores. By counting the number of scores within that range and dividing by the total number of scores, then multiplying by 100, you can calculate the percentage. Without specific data, it's impossible to provide an exact percentage.
What percentage of scores fall between 0 and -2 in a normal distribution?
2
The mean of a distribution of scores is the?
The mean of a distribution of scores is the average.
What percentage of normally distributed scores lie under the normal curve?
100%. And that is true for any probability distribution.
What percentage of scores fall within -3 and plus 3 standard deviations around the mean in a normal distribution?
99.7% of scores fall within -3 and plus 3 standard deviations around the mean in a normal distribution.
What percentage of scores in a normal distribution would fall between z-scores of 1 and -2?
3
When are credit scores used to determine loan percentages?
Credit scores are used to determine loan percentages when a person applies for a loan. If a person has a low credit score, the percentages of interest are higher, whereas higher credit scores result in lower loan percentage rates.
How do you find the scores at the 60th percentile in a set of 200 scores?
You can't do this without knowing the distribution of scores.
How are tests curved to determine final grades?
Tests are curved by adjusting scores to a predetermined distribution, such as a bell curve, to determine final grades. This helps account for variations in difficulty and ensures fairness in grading.
How would you characterize the distribution of scores in a normal distribution?
They are said to be Normally distributed.
When the mean of a distribution of scores of measures is higher than the median the distribution would be?
The distribution is skewed to the right.
