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The answer is about 16%

Using the z-score formula(z = (x-u)/sd) the z score is 1.

This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.

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Q: Scores on the sat exam approximate a normal distribution with µ equals 500 and sd equals 100 use this distribution to determine the percentage of sat scores that fall above 600?
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