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The answer is about 16%

Using the z-score formula(z = (x-u)/sd) the z score is 1.

This means that we want the percentage above 1 standard deviation. We know from the 68-95-99.7 rule that 68 percent of all the data fall between -1 and 1 standard deviation so there must be about 16% that falls above 1 standard deviation.

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Related Questions

What percentage of scores are between 61 and 82?

To determine the percentage of scores between 61 and 82, you would need to know the distribution of the scores (e.g., normal distribution) and the total number of scores. If the data is normally distributed, you can use the mean and standard deviation to find the percentage of scores in that range using a z-score table. Without specific data, it isn't possible to provide an exact percentage.


What percent of the scores are between 63 and 90?

To determine the percentage of scores between 63 and 90, you would need the complete dataset or a statistical summary (like a frequency distribution or histogram) of the scores. By counting the number of scores within that range and dividing by the total number of scores, then multiplying by 100, you can calculate the percentage. Without specific data, it's impossible to provide an exact percentage.


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