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Q: If X is real how can you find the max value of X?

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The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.

The domain would be: all reall numbers. The domain is which 'X' values you can insert into 'X' and get a value for 'Y'. Since any real number could be inserted to create a 'Y' value, the answer is:all real numbers.

4.2 is a pure real (rational) number. It has no specific X value.

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In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.

To find the largest of three values you first need to find the largest of two values and then compare that value with the third value. To achieve this we need a function (conventionally named "max"): int max (const int a, const int b) { return (a > b) ? a : b; } That is, if a is greater than b, return a, otherwise return b. To find the greatest of three values, x, y and z: int largest = max (max (x, y), z);

ax2 + bx + c = 0 , find the value of x . b2-4ac>o x is real (2 different values will solve) b2-4ac=o -> a double root (a single real number will solve it) x=real numbers. b2-4ac<0 x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)

int findMax(int x, int y, int z) { int max = x; if(max < y) max = y; if(max < z) max = z; return max; }

180-x...... hahaahahaaa

The domain could be the real numbers, in which case, the range would be the non-negative real numbers.

.75/x=.33

The answer will depend on what x is.

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