187.10
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
187.10
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
the answer is 32
21.2 sq inches.
It's impossible to have an area in cubic units.
To find the area of an equilateral triangle, you can use the formula: area = (sqrt(3)/4) * s^2 where s is the length of one side of the triangle. If the length of one side of the triangle is 6 cm, the area of the triangle is: area = (sqrt(3)/4) * 6^2 = (sqrt(3)/4) * 36 = (3.46/4) * 36 = 13.83 * 36 = 498.68 Rounded to one decimal place, the area of the triangle is approximately 499 cm^2.
34.2497 rounded to 1 decimal place equals ... 34.2! I think ^.^
First find the perpendicular height (h) of the triangle using Pythagoras.h = sqrt (102 - 52) = sqrt 75 = 8.660254038...Now, area of a triangle = 1/2 base x height.So: area = 1/2 x 10 x 8.660254038 = 43.3 (1 decimal place.)
7.2
Each angle in an equilateral triangle is 60 degrees. In order to create a regular tessellation of an area, we need for the angles of the polygons we are putting near each other to sum to 360 degrees. If you place six equilateral triangles so that all of them share a vertex, and each triangle is adjacent to two others, you get 60*6 = 360 degrees in that vertex. Please see related link for a demo of a triangular tessellation.
The correct answer is 0.74