187.10
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
the answer is 32
It's impossible to have an area in cubic units.
use pythagorean theorem. it helps to draw a picture. draw an invisible line from one vertex straight to the opposite side. the hypotenuse is 9, and the shorter leg is half of 9, or 4.5. 81= 20.25 + h squared. height equals 7.7942 and then u round it to 7.8 (x
6.5- you round it until it has one decimal.
187.10
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.
the answer is 32
Area of equilateral triangle: 0.5*7*7*sin(60 degrees) = 21.2 square inches
It's impossible to have an area in cubic units.
To find the area of an equilateral triangle, you can use the formula: area = (sqrt(3)/4) * s^2 where s is the length of one side of the triangle. If the length of one side of the triangle is 6 cm, the area of the triangle is: area = (sqrt(3)/4) * 6^2 = (sqrt(3)/4) * 36 = (3.46/4) * 36 = 13.83 * 36 = 498.68 Rounded to one decimal place, the area of the triangle is approximately 499 cm^2.
Area of equilateral triangle: 0.5*12*12*sin(60 degrees) = 187 square cm
The area is 99.0 square units.
7.2
166.30
0.3306 = 0.33 to 2 dp.